For position-time $(x-t)$ curve as shown in figure, the velocity-time $(v-t)$ curve will be

Question

Aicharya · Accepted Answer

$0-t_{1} ightarrow$ uniformly retarded motion $t_{1}-t_{2} ightarrow$ particle at rest $t_{2}-t_{3} ightarrow$ uniform negative velocity $t_{3}-t_{4} ightarrow$ particle at rest $t_{4}-t_{5} ightarrow$ uniform negative velocity $	herefore \quad$

For position-time $(x-t)$ curve as shown in figure, the velocity-time $(v-t)$ curve will be

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