For polyatomic gases, the ratio of molar specific heat at constant pressure to constant volume is…
For polyatomic gases, the ratio of molar specific heat at constant pressure to constant volume is $(\mathrm{f}=$ degrees of freedom $)$
$\frac{2+\mathrm{f}}{3+\mathrm{f}}$
$\frac{3+\mathrm{f}}{2+\mathrm{f}}$
$\frac{3+\mathrm{f}}{4+\mathrm{f}}$
$\frac{4+f}{3+f}$
Solution
For polyatomic gases, molar-specific heat at constant volume is $\mathrm{C}_{\mathrm{V}}=(3+\mathrm{f}) \mathrm{R}$ and Molar-specific heat at constant pressure is $\mathrm{C}_{\mathrm{P}}=(4+\mathrm{f}) \mathrm{R}$
$\therefore \quad \frac{\mathrm{C}_{\mathrm{P}}}{\mathrm{C}_{\mathrm{V}}}=\frac{4+\mathrm{f}}{3+\mathrm{f}}$
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