For perimeter $20$, $\angle B = 50^{\circ}, \angle C = 70^{\circ}$, $\angle A$ is

For perimeter $20$, $\angle B = 50^{\circ}, \angle C = 70^{\circ}$, $\angle A$ is
  1. $60^{\circ}$
  2. $50^{\circ}$
  3. $120^{\circ}$
  4. $70^{\circ}$

Solution

$180 - 50 - 70 = 60^{\circ}$.

Asked in: MH-SSC-9

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