For isochoric process, the first law of thermodynamics can be expressed as

For isochoric process, the first law of thermodynamics can be expressed as
  1. $\Delta \mathrm{U}=\mathrm{Qv}$
  2. $-\Delta \mathrm{U}=\mathrm{Q}-\mathrm{P} \Delta \mathrm{V}$
  3. $-\Delta \mathrm{U}=-\mathrm{W}$
  4. $\mathrm{W}=-\mathrm{Q}$

Solution

For Isochoric process, Volume remains constant. $\begin{aligned} & \Delta \mathrm{V}=0 \\ & \mathrm{~W}=-\mathrm{P} \Delta \mathrm{V}=0 \end{aligned}$ First Law of thermodynamics, $\Delta \mathrm{U}=\mathrm{q}+\mathrm{W}$ At constant volume condition, $\left(\mathrm{W}=0, \mathrm{q}=\mathrm{q}_{\mathrm{v}}\right)$ $\Delta \mathrm{U}=\mathrm{q}_{\mathrm{v}}$ Or $\Delta \mathrm{U}=\mathrm{Q}_{\mathrm{V}}$

Asked in: MHT CET 2021 (24 Sep Shift 2)

Practice more Chemical Thermodynamics questions on Aicharya