For $k0$, if $\mathrm{k} \sqrt{-1}$ is a root of the equation $x^4+6 x^3-16 x^2+24 x-80=0$ then $k^2=$

Question

For $k>0$, if $\mathrm{k} \sqrt{-1}$ is a root of the equation $x^4+6 x^3-16 x^2+24 x-80=0$ then $k^2=$

Aicharya · Accepted Answer

No solution. Refer to answer key.

For $k>0$, if $\mathrm{k} \sqrt{-1}$ is a root of the equation $x^4+6 x^3-16 x^2+24 x-80=0$ then $k^2=$