For (i) \(\mathrm{I}^{-}\), (ii) \(\mathrm{Cl}^{-}\), (iii) \(\mathrm{Br}^{-}\), the increasing order of…

For (i) \(\mathrm{I}^{-}\), (ii) \(\mathrm{Cl}^{-}\), (iii) \(\mathrm{Br}^{-}\), the increasing order of nucleophilicity would be
  1. \(\mathrm{Cl}^{-} < \mathrm{Br}^{-} < 1^{-}\)
  2. \(\mathrm{I}^{-} < \mathrm{Cl}^{-} < \mathrm{Br}^{-}\)
  3. \(\mathrm{Br}^{-} < \mathrm{Cl}^{-} < \mathrm{I}^{-}\)
  4. \(\mathrm{I}^{-} < \mathrm{Br}^{-} < \mathrm{Cl}^{-}\)

Solution

Nucleophilicity increases down the group in a periodic table. $\mathrm{I}^{-} > \mathrm{Br} > \mathrm{Cl}^{-} > \mathrm{F}^{-}$

Asked in: NEET 2007

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