For given data $N=60, \sum X^2=18000$ and $\sum X=960$, then variance of data is
For given data $N=60, \sum X^2=18000$ and $\sum X=960$, then variance of data is
- 54
- 34
- 22
- 44
Solution
Variance $=\frac{\sum x^2}{N}-\left(\frac{\sum x}{N}\right)^2=\frac{18000}{60}-\left(\frac{960}{60}\right)^2=300-256=44$
Asked in: MHT CET 2022 (10 Aug Shift 1)
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