For given data $N=60, \sum X^2=18000$ and $\sum X=960$, then variance of data is

For given data $N=60, \sum X^2=18000$ and $\sum X=960$, then variance of data is
  1. 54
  2. 34
  3. 22
  4. 44

Solution

Variance $=\frac{\sum x^2}{N}-\left(\frac{\sum x}{N}\right)^2=\frac{18000}{60}-\left(\frac{960}{60}\right)^2=300-256=44$

Asked in: MHT CET 2022 (10 Aug Shift 1)

Practice more Probability questions on Aicharya