For electron in ' 2 s ' and ' 2 p ' orbitals, the orbital angular momentum values, respectively are :

For electron in ' 2 s ' and ' 2 p ' orbitals, the orbital angular momentum values, respectively are :
  1. $\sqrt{2} \frac{\mathrm{~h}}{2 \pi}$ and 0
  2. $\frac{\mathrm{h}}{2 \pi}$ and $\sqrt{2} \frac{\mathrm{~h}}{2 \pi}$
  3. 0 and $\sqrt{6} \frac{\mathrm{~h}}{2 \pi}$
  4. 0 and $\sqrt{2} \frac{\mathrm{~h}}{2 \pi}$

Solution

$\begin{aligned} & \text { Orbital angular momentum }=\sqrt{\ell(\ell+1)} \frac{\mathrm{h}}{2 \pi} \\ & \therefore \quad \text { For } 2 \mathrm{~s} \text { orbital }: \ell=0 \\ & \text { Orbital angular momentum }=0 \\ & \therefore \quad \text { For } 2 \mathrm{p} \text { orbital }: \ell=1 \\ & \quad \begin{aligned} \text { Orbital angular momentum } & =\sqrt{1(1+2)} \frac{\mathrm{h}}{2 \pi} \\ & =\sqrt{2} \frac{\mathrm{~h}}{2 \pi}\end{aligned}\end{aligned}$

Asked in: JEE Main 2025 (03 Apr Shift 2)

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