For $\mathrm{X} \sim \mathrm{B}(\mathrm{n}, \mathrm{p})$, if $\mathrm{p}=0.6, \mathrm{E}(\mathrm{X})=6$, then $\operatorname{Var}(\mathrm{X})=$

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Aicharya · Accepted Answer

We have $p=0.6$ and $n p=6 \Rightarrow n=10$ $	herefore \operatorname{Var}(\mathrm{X})=\mathrm{npq}=(10)(0.6)(0.4)=2.4$

For $\mathrm{X} \sim \mathrm{B}(\mathrm{n}, \mathrm{p})$, if $\mathrm{p}=0.6, \mathrm{E}(\mathrm{X})=6$,…