For $BC = 5, \angle B = 60^{\circ}, AB - AC = 2$, $BX$ equals

For $BC = 5, \angle B = 60^{\circ}, AB - AC = 2$, $BX$ equals
  1. $2$
  2. $5$
  3. $7$
  4. $3$

Solution

$BX = AB - AC = 2$.

Asked in: MH-SSC-9

Practice more Constructions of Triangles questions on Aicharya