For a ∈ R ,   a > 1 , let lim n → ∞ ⁡ 1 + 2 3 + … + n 3 n 7 / 3 1 a n…

For aR, a>1, let limn1+23++n3n7/31an+12+1an+22++1an+n2=54. Then the possible value(s) of a is/are:
  1. 8
  2. -9
  3. -6
  4. 7

Solution

Let S=limn1+213+313++n13n731an+12++1an+n2
S=limnr=1nr13n73r=1n1na+r2
S=limnr=1nrn131n×n13n73r=1n1a+rn21n2
S=limnr=1nrn13.1nr=1n1a+rn21n
S=01x13dx011a+x2.dx
S=x434301-1x+a01
S=341a-1a+1=54
1aa+1=172
a2+a-72=0
a=8 or a=-9

Asked in: JEE Advanced 2019 (Paper 2)

Practice more Limits questions on Aicharya