For any two non-zero vectors $\bar{a}$ and $\bar{b},(a \bar{b}+b \bar{a}) \cdot(a \bar{b}-b \bar{a})$ is

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Aicharya · Accepted Answer

$\begin{aligned} & (a \vec{b}+b \vec{a}) \cdot(a \vec{b}-b \vec{a}) \ & =a^2(\vec{b} \cdot \vec{b})-b^2(\vec{a} \cdot \vec{a}) \ & =a^2 b^2-b^2 a^2 \ & =0\end{aligned}$

For any two non-zero vectors $\bar{a}$ and $\bar{b},(a \bar{b}+b \bar{a}) \cdot(a \bar{b}-b \bar{a})$ is

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