For any integer $\mathrm{n} \geq 2$, if $\mathrm{I}_n=\int \cot ^n x d x$ then $\mathrm{I}_5=$
- $\frac{-\cot ^4 x}{4}+\frac{\cot ^2 x}{2}+\log |\sin x|+c$
- $\frac{-\cot ^4 x}{4}+\frac{\cot ^2 x}{2}-\log |\sin x|+c$
- $\frac{\cot ^4 x}{4}+\frac{\cot ^2 x}{2}+\log |\cos x|+c$
- $\frac{\cot ^4 x}{4}-\frac{\cot ^2 x}{2}-\cot x+c$
Solution
Asked in: AP EAMCET 2018 (24 Apr Shift 2)