For an ideal gas, $\mathrm{R}=\frac{2}{3} \mathrm{C}_{\mathrm{v}}$. This suggests that the gas consists of…

For an ideal gas, $\mathrm{R}=\frac{2}{3} \mathrm{C}_{\mathrm{v}}$. This suggests that the gas consists of molecule, which are $[\mathrm{R}=$ universal gas constant $]$
  1. polyatomic
  2. diatomic
  3. monoatomic
  4. a mixture of diatomic and polyatomic molecules

Solution

For an ideal gas $\begin{aligned} & C_v=\frac{f}{2} R \\ & \text { Or } R=\frac{2}{f} C_v \end{aligned}$ Hence, $\mathrm{f}=3$ Thus, gas is monoatomic. .

Asked in: MHT CET 2021 (24 Sep Shift 1)

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