For an ideal gas four processes are marked as 1 2,3 and 4 on $\mathrm{P}-\mathrm{V}$ diagram as shown in…

For an ideal gas four processes are marked as 1 2,3 and 4 on $\mathrm{P}-\mathrm{V}$ diagram as shown in figure. The amount of heat supplied to the gas in the process $1,2,3$ and 4 are $\mathrm{Q}_{1}, \mathrm{Q}_{2}, \mathrm{Q}_{3}$ and $\mathrm{Q}_{4}$ respectively, then correct order of heat supplied to the gas is $[\mathrm{AB}$ is process- $1, \mathrm{AC}$ is process- $2, \mathrm{AD}$ is adiabatic process-3 and $\mathrm{AE}$ is process-4]
  1. $\quad \mathrm{Q}_{1}>\mathrm{Q}_{2}>\mathrm{Q}_{3}>\mathrm{Q}_{4}$
  2. $\quad Q_{1}>Q_{2}>Q_{4}>Q_{3}$
  3. $\quad Q_{1}>Q_{4}>Q_{2}>Q_{3}$
  4. $\quad \mathrm{Q}_{1} < \mathrm{Q}_{2} < \mathrm{Q}_{3} < \mathrm{Q}_{4}$

Solution

In process- 1 heat supplied $=$ area under $\mathrm{AB}$ curve $+\mathrm{n} \times \mathrm{c}_{\mathrm{p}} \times 100 \quad$ (isochoric process) In process-2 heat supplied $=$ area under $\mathrm{AC}$ curve (isothermal process) In process-3 heat supplied $=0$ (adiabatic process) In process- 4 heat supplied $=\mathrm{n} \times \mathrm{c}_{\mathrm{v}}(\mathrm{T}-600)$
(isobaric process) ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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