For an endothermic reaction, energy of activation is $E_a$ and enthalpy of reaction is $\Delta H$ (both of…
- less than $\Delta \mathrm{H}$
- equal to $\Delta \mathrm{H}$
- more than $\Delta \mathrm{H}$
- equal to zero
Solution
where, $\mathrm{E}_{\mathrm{a}}=$ activation energy of forward reaction
$\mathrm{E}_{\mathrm{a}}^{\prime}=$ activation energy of backward reaction
$\Delta \mathrm{H}=$ enthalpy of the reaction
From the above diagram,
$\mathrm{E}_{\mathrm{a}}=\mathrm{E}_{\mathrm{a}}^{\prime}+\Delta \mathrm{H}$
Thus, $\mathrm{E}_{\mathrm{a}} > \Delta \mathrm{H}$Asked in: NEET 2010 (Screening)