For an amplitude modulated wave, the maximum and minimum amplitudes are $12 \mathrm{~V}$ and $3 \mathrm{~V}$ respectively. Then the modulation index is

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Aicharya · Accepted Answer

Given, $\mathrm{V}_{\max }=12 \mathrm{~V}$ and $\mathrm{V}_{\min }=3 \mathrm{v}$ modulation index, $\mu=\frac{V_{\max }-V_{\min }}{V_{\max }+V_{\min }}$ $=\frac{12-3}{12+3}=\frac{9}{15}=0.6$

For an amplitude modulated wave, the maximum and minimum amplitudes are $12 \mathrm{~V}$ and $3 \mathrm{~V}$…

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