For all values of $\theta$, the values of $3-\cos \theta+\cos \left(\theta+\frac{\pi}{3}\right)$ lie in the…
For all values of $\theta$, the values of $3-\cos \theta+\cos \left(\theta+\frac{\pi}{3}\right)$ lie in the interval :
- $[-2,3]$
- $[-2,1]$
- $[2,4]$
- $[1,5]$
Solution
$3-\cos \theta+\cos \left(\theta+\frac{\pi}{3}\right)$
$=3-\cos \theta+\cos \theta \cdot \cos \frac{\pi}{3}-\sin \theta \cdot \sin \frac{\pi}{3}$
$=3-\cos \theta+\frac{1}{2} \cos \theta-\frac{\sqrt{3}}{2} \sin \theta$
$=3-\frac{1}{2} \cos \theta-\frac{\sqrt{3}}{2} \sin \theta$
$=3-\left[\sin \frac{\pi}{6} \cos \theta+\cos \frac{\pi}{6} \sin \theta\right]$
$=3-\sin \left(\theta+\frac{\pi}{6}\right)$
Since $-1 \leq \sin \theta \leq 1$
$\therefore$ The value of expression lies in $[2,4]$.
Asked in: AP EAMCET 2006
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