For all values of $\theta$, the values of $3-\cos \theta+\cos \left(\theta+\frac{\pi}{3}\right)$ lie in the…

For all values of $\theta$, the values of $3-\cos \theta+\cos \left(\theta+\frac{\pi}{3}\right)$ lie in the interval :
  1. $[-2,3]$
  2. $[-2,1]$
  3. $[2,4]$
  4. $[1,5]$

Solution

$3-\cos \theta+\cos \left(\theta+\frac{\pi}{3}\right)$ $=3-\cos \theta+\cos \theta \cdot \cos \frac{\pi}{3}-\sin \theta \cdot \sin \frac{\pi}{3}$ $=3-\cos \theta+\frac{1}{2} \cos \theta-\frac{\sqrt{3}}{2} \sin \theta$ $=3-\frac{1}{2} \cos \theta-\frac{\sqrt{3}}{2} \sin \theta$ $=3-\left[\sin \frac{\pi}{6} \cos \theta+\cos \frac{\pi}{6} \sin \theta\right]$ $=3-\sin \left(\theta+\frac{\pi}{6}\right)$ Since $-1 \leq \sin \theta \leq 1$ $\therefore$ The value of expression lies in $[2,4]$.

Asked in: AP EAMCET 2006

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