For all $n \in N,(n+24)(n+25)(n+26)(n+27)$ is divisible by

For all $n \in N,(n+24)(n+25)(n+26)(n+27)$ is divisible by
  1. 27
  2. 26
  3. 29
  4. 24

Solution

Since, $(n+24)(n+25)(n+26)(n+27)$ is a product of consecutive four natural numbers. $\therefore$ It is divisible by $4 !=24$

Asked in: AP EAMCET 2021 (25 Aug Shift 1)

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