For a > 0 , let the curves C 1 : y 2 = a x and C 2 : x 2 = a y intersect at origin O and a point P . Let…

For a>0, let the curves C1:y2=ax and C2:x2=ay intersect at origin O and a point P. Let the line x=b0<b<a intersect the chord OP and the x -axis at points Q and R, respectively. If the line x=b bisects the area bounded by the curves, C1 and C2, and the area of OQR=12, then ‘ a ’ satisfies the equation:
  1. x6-6x3+4=0
  2. x6-12x3+4=0
  3. x6+6x3-4=0
  4. x6-12x3-4=0

Solution

0bax-x2adx=a26

23ab32-b33a=a26           ...1

Also area of ΔOQR=12 

12b2=12b=1

Put in 1

4aa-2=a3

a6+4a3+4=16a3

a6-12a3+4=0

Asked in: JEE Main 2020 (08 Jan Shift 1)

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