For a triangle with the sides of lengths 6,5 and 9, then the radius of the circle is
For a triangle with the sides of lengths 6,5 and 9, then the radius of the circle is
- \(\sqrt{3}\)
- \(\sqrt{2}\)
- \(\sqrt{5}\)
- \(\frac{\sqrt{3}}{\sqrt{2}}\)
Solution
\(\begin{aligned}
\text {In radius } & =\frac{\Delta}{s}=\frac{\sqrt{s(s-a)(s-b)(s-c)}}{s} \\
& =\frac{\sqrt{10(4)(5)(1)}}{10}=\sqrt{2}
\end{aligned}\)
Asked in: AP EAMCET 2020 (17 Sep Shift 1)
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