For a triangle formed by $(0,0),(4,0)$ and $(3,4)$, the orthocenter is

Question

Aicharya · Accepted Answer

Let Plotting the coordinates $\mathrm{A}(0,0), \mathrm{B}(4,0)$ and $\mathrm{C}(3$,4)

Let $\mathrm{AC}$ is perpendicular to $\mathrm{OB}$ Hence $\mathrm{AC} \equiv \mathrm{x}=3$...(i) Let $\mathrm{OD}$ is perpendicular to $\mathrm{BC}$ $\Rightarrow \mathrm{OD}=\mathrm{y}=\frac{1}{4} \mathrm{x}$...(ii) from (i) and (ii) Or the center $\cong\left(3, \frac{3}{4}\right)$

For a triangle formed by $(0,0),(4,0)$ and $(3,4)$, the orthocenter is

Solution