For a transistor, current gain $(\beta)=50$. To change the collector current by $350 \mu \mathrm{~A}$, the base current should be changed by

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Aicharya · Accepted Answer

$\begin{aligned} & \beta=\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}} \ 	herefore \quad & \Delta \mathrm{I}_{\mathrm{B}}=\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\dot{\beta}}=\frac{350}{50} \mu \mathrm{~A}\end{aligned}$

For a transistor, current gain $(\beta)=50$. To change the collector current by $350 \mu \mathrm{~A}$, the…

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