For a series LCR circuit with R = 100   Ω ,   L = 0 . 5   mH and C = 0 . 1   pF…

For a series LCR circuit with R=100 Ω, L=0.5 mH and C=0.1 pF connected across 220 V-50 Hz AC supply, the phase angle between
current and supplied voltage and the nature of the circuit is:
  1. 0°, resistive circuit
  2. ≈90°, predominantly inductive circuit
  3. 0°, resonance circuit
  4. ≈90°, predominantly capacitive circuit

Solution

R=100 Ω

XL=ωL=50π×10-3

XC=1ωC=1011100π

XC≫XL

and XC-XL≫R

Asked in: JEE Main 2021 (20 Jul Shift 2)

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