For a series L C R circuit, I vs ω curve is shown (a) To the left of ω r , the circuit is mainly capacitive. (b) To the left of ω r , the circuit is mainly inductive. (c) At ω r , impedance of the circuit is equal to the resistance of the circuit. (d) At ω r , impedance of…

Question

For a series L C R circuit, I vs &#969; curve is shown (a) To the left of &#969; r , the circuit is mainly capacitive. (b) To the left of &#969; r , the circuit is mainly inductive. (c) At &#969; r , impedance of the circuit is equal to the resistance of the circuit. (d) At &#969; r , impedance of the circuit is 0 . Choose the most appropriate answer from the options given below.

Aicharya · Accepted Answer

The impedance of an AC circuit is given by, $Z = \sqrt{R^{2} + {(X_{C} - X_{L})}^{2}}$ .

For current to be maximum $Z$ should be minimum. The value of $Z$ will be minimum when $X_{C} - X_{L} = 0$ . Therefore, the value of $Z = R$ . Hence, statement C is correct and statement D is wrong.

To the left of $ω_{r}$ i.e. when $ω < ω_{r}$ , $X_{C} > X_{L}$ . Therefore, the circuit is mainly capacitive. Hence, statement A is correct and statement B is wrong.

For a series L C R circuit, I vs ω curve is shown (a) To the left of ω r , the circuit is mainly…

Solution

For a series L C R circuit, I vs &#969; curve is shown (a) To the left of &#969; r , the circuit is mainly…

Solution

For a series L C R circuit, I vs ω curve is shown (a) To the left of ω r , the circuit is mainly…