For a sequence $\left(t_{n}\right)$ if $s_{n}=7\left(3^{n}-1\right)$, then $t_{n}=$

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Aicharya · Accepted Answer

A sequence; $t_{n} ;$ $\begin{aligned} s_{n} &=7\left(3^{n-1}ight) \ s_{n-1} &=7\left(3^{n-1}-1ight) \ & \end{aligned}$ $\begin{aligned} t_{n} &=s_{n}-s_{n-1} \ t_{n} &=7\left(3^{n}-3^{n-1}ight) \ &=7 \cdot 3^{n-1} \cdot 2 \ &=14 \cdot 3^{n-1} \end{aligned}$

For a sequence $\left(t_{n}\right)$ if $s_{n}=7\left(3^{n}-1\right)$, then $t_{n}=$

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