For a reversible gaseous reaction $\mathrm{N}_{2}+3 \mathrm{H}_{2} ightleftharpoons 2 \mathrm{NH}_{3}$ at…
For a reversible gaseous reaction $\mathrm{N}_{2}+3 \mathrm{H}_{2} ightleftharpoons 2 \mathrm{NH}_{3}$ at equilibrium, if some moles of $\mathrm{H}_{2}$ are replaced by same number of moles of $\mathrm{T}_{2}$ (T is tritium, isotope of $\mathrm{H}$ and assume isotopes do not have different chemical properties) without affecting other parameter, then:
the sample of ammonia obtained after sometime will be radioactive.
moles of $\mathrm{N}_{2}$ after the change will be different as compared to moles of $\mathrm{N}_{2}$ present before the change
the value of $\mathrm{K}_{\mathrm{p}}$ or $\mathrm{K}_{\mathrm{c}}$ will change
the average molecular mass of new equilibrium will be same as that of old equilibrium
Solution
Since $T_{2}$ has similar chemical properties as $\mathrm{H}_{2}$ so upon mixing, $\mathrm{NH}_{2} \mathrm{~T}$ and $\mathrm{NHT}_{2}$ are formed.
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