For a reaction $r=k[A][B]^2$, if concentration of $A$ is doubled the rate of reaction
For a reaction $r=k[A][B]^2$, if concentration of $A$ is doubled the rate of reaction
- increases by 2
- decrease by $\frac{1}{2}$
- increases by 4
- decreases by 2
Solution
$\begin{aligned}
& \text { Rate }=\mathrm{k}[\mathrm{~A}][\mathrm{B}]^2 \\
& (\text { Rate })_2=\mathrm{k}[2 \mathrm{~A}][\mathrm{B}]^2=\mathrm{k} \times 2[\mathrm{~A}][\mathrm{B}]^2 \\
\therefore \quad & (\text { Rate })_2=2 \times \text { Rate }
\end{aligned}$
i.e., rate of reaction increases by a factor of 2 .
Asked in: MHT CET 2024 (15 May Shift 2)
Practice more Chemical Kinetics questions on Aicharya