For a reaction $\mathrm{A}+2 \mathrm{~B} ightarrow \mathrm{C}$, the amount of formed by starting the…

For a reaction $\mathrm{A}+2 \mathrm{~B} ightarrow \mathrm{C}$, the amount of formed by starting the reaction with 5 moles of $\mathrm{A}$ and 8 moles of $\mathrm{B}$ is
  1. 5 moles
  2. 8 moles
  3. 16 moles
  4. 4 moles

Solution

$\mathrm{A}+2 \mathrm{~B} \longrightarrow \mathrm{C}$
1 mole of A reacts with 2 moles of $B$ to give $1 \mathrm{~mol}$ of $\mathrm{C}$.
$\therefore 5$ moles of A would react with 10 moles of B to give 5 moles of $C$. But, only 8 moles of $B$ are available
$\therefore \mathrm{B}$ acts as a limiting reagent.
2 moles of B gives 1 mole of C
$\therefore \quad 8$ moles of $B$ will give $1 / 2 \times 8=4$ moles of $C$. ~

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more CHEMICAL KINETICS questions on Aicharya