For a reaction $\frac{1}{2} \mathrm{~A} ightarrow 2 \mathrm{~B}$, rate of disappearance of '…
- $-\frac{\mathrm{d}[\mathrm{A}]}{\mathrm{dt}}=\frac{1}{4} \frac{\mathrm{d}[\mathrm{B}]}{\mathrm{dt}}$
- $-\frac{\mathrm{d}[\mathrm{A}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{B}]}{\mathrm{dt}}$
- $-\frac{\mathrm{d}[\mathrm{A}]}{\mathrm{dt}}=4 \frac{\mathrm{d}[\mathrm{B}]}{\mathrm{dt}}$
- $-\frac{\mathrm{d}[\mathrm{A}]}{\mathrm{dt}}=\frac{1}{2} \frac{\mathrm{d}[\mathrm{B}]}{\mathrm{dt}}$
Solution
$=\frac{-d[A]}{\frac{1}{2} d t}=\frac{d B}{2 d t}$ or $\frac{-d[A]}{d t}=\frac{1}{4} \frac{d[B]}{d t}$ *
Asked in: JEE-TOPICTESTS-CHEMISTRY