For a reaction \(\mathrm{A} \xrightarrow{\mathrm{K}_1} \mathrm{~B} \xrightarrow{\mathrm{K}_2} \mathrm{C}\)…

For a reaction \(\mathrm{A} \xrightarrow{\mathrm{K}_1} \mathrm{~B} \xrightarrow{\mathrm{K}_2} \mathrm{C}\) If the rate of formation of \(B\) is set to be zero then the concentration of \(B\) is given by :
  1. \(\left(\mathrm{K}_1+\mathrm{K}_2\right)[\mathrm{A}]\)
  2. \(\left(\mathrm{K}_1 / \mathrm{K}_2\right)[\mathrm{A}]\)
  3. \(\left(\mathrm{K}_1-\mathrm{K}_2\right)[\mathrm{A}]\)
  4. \(\mathrm{K}_1 \mathrm{~K}_2[\mathrm{~A}]\)

Solution

Rate of formation of $B$ is $\begin{aligned} & \frac{\mathrm{d}[\mathrm{B}]}{\mathrm{dt}}=\mathrm{k}_1[\mathrm{~A}]-\mathrm{k}_2[\mathrm{~B}] \\ & 0=\mathrm{k}_1[\mathrm{~A}]-\mathrm{k}_2[\mathrm{~B}] \\ & \left(\frac{\mathrm{k}_1}{\mathrm{k}_2}\right)[\mathrm{A}]=[\mathrm{B}]\end{aligned}$

Asked in: JEE Main 2024 (08 Apr Shift 2)

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