For a ray of light, the critical angle is minimum when it travels from
For a ray of light, the critical angle is minimum when it travels from
air to glass.
glass to water.
water to glass.
glass to air.
Solution
$\sin c=\frac{1}{\mu}$
$a\mu_{\mathrm{w}}=\frac{4}{3}, a \mu_{\mathrm{g}}=\frac{3}{2}, w \mu_{\mathrm{g}}=\frac{\mathrm{a} \mu_{\mathrm{g}}}{\mathrm{a} \mu_{\mathrm{w}}}=\frac{9}{8}$
Critical angle will be maximum when refractive index of the denser medium w.r.t. the rarer medium is minimum.
$w \mu_{8}=\frac{9}{8}$ is minimum