For a random variable $X$ if $P(X=k)=\frac{(k+1) a}{3^k}$ for $k=0,1,2, \ldots$ then $a=$

For a random variable $X$ if $P(X=k)=\frac{(k+1) a}{3^k}$ for $k=0,1,2, \ldots$ then $a=$
  1. $\frac{2}{3}$
  2. $\frac{4}{9}$
  3. $\frac{8}{27}$
  4. $\frac{16}{81}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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