For a perfect gas, two pressures P 1 and P 2 are shown in figure. The graph shows

For a perfect gas, two pressures P1 and P2 are shown in figure. The graph shows

  1. P1>P2
  2. P1<P2
  3. P1=P2
  4. Insufficient data to draw any conclusion

Solution

We know that the ideal gas equation of gas is

PV=nRT

Keeping the temperature constant, we have, V∝1P

As seen from graph, V2>V1, so P1>P2.

Asked in: JEE Main 2022 (27 Jun Shift 2)

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