For a perfect black body, the absorption coefficient is

For a perfect black body, the absorption coefficient is
  1. \(a=1\)
  2. \(a < 1\)
  3. \(a>1\)
  4. \(a=0\)

Solution

A perfectly black body absorbs \(100 \%\) of radiation incident on it, hence absorption coefficient \(\left(a_r\right)\) is given as \(\begin{aligned} a_r & =\frac{\text { amount of absorb radiation }\left(Q_a\right)}{\text { amount of incident radiation }\left(Q_i\right)} \\ & =\frac{Q_a}{Q_i}=\frac{Q_a}{Q_a} \quad\left[\because Q_a=Q_i\right] \\ & =1 \end{aligned}\)

Asked in: AP EAMCET 2020 (18 Sep Shift 1)

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