For a particular ideal gas which of the following graphs represents the variation of mean squared velocity…
Solution
& \mathrm{V}_{\mathrm{ms}}=\sqrt{\frac{3 \mathrm{RT}}{\mathrm{M}}} \\ & \mathrm{~V}_{\mathrm{rms}}^2=3 \mathrm{RT} / \mathrm{M}
\end{aligned}$
Hence we can conclude that $\mathrm{V}_{\mathrm{rms}}^2$ is directly proportional to temperature
$\mathrm{y}=\mathrm{mx}$
$\Rightarrow$ Graph will be straight line
Asked in: JEE Main 2025 (28 Jan Shift 1)



