For a particle performing S.H.M., the displacement-time graph is as shown. For that particle the force-time…

For a particle performing S.H.M., the displacement-time graph is as shown. For that particle the force-time graph is correctly shown in graph


  1. (A)
  2. (B)
  3. (C)
  4. (D)

Solution

For a particle performing S.H.M. $F=-k x=-k A \sin \omega t$ The force time graph will be inverted distance time graph. ~

Asked in: MHT CET 2020 (13 Oct Shift 2)

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