For a particle performing linear S.H.M., its average speed over one oscillation is ( $A=$ amplitude of S.H.M…
For a particle performing linear S.H.M., its average speed over one oscillation is
( $A=$ amplitude of S.H.M., $n=$ frequency of oscillation)
4nA
8nA
2nA
6nA
Solution
Distance covered per oscillation, $s=4 a$
Time taken for one oscillation, $T=\frac{1}{n}$
Hence, the average speed per oscillation $v_{a v}=\frac{S}{T}=4 a n$