For a particle in uniform circular motion, the acceleration a → at any point P R , θ on the circular path of radius R is (when θ is measured from the positive x -axis and v is uniform speed):

Question

For a particle in uniform circular motion, the acceleration a &#8594; at any point P R , &#952; on the circular path of radius R is (when &#952; is measured from the positive x -axis and v is uniform speed):

Aicharya · Accepted Answer

Acceleration of a particle in uniform circular motion is directed towards the centre of the circle and its magnitude is $\frac{v^{2}}{R}$ . The radius vector is $\vec{r} = R \cos θ \hat{i} + R \sin θ \hat{j}$

Therefore, $\vec{a} = - \frac{v^{2}}{R} \hat{r} = \frac{v^{2}}{R} (- \cos θ \hat{i} - \sin θ \hat{j})$

For a particle in uniform circular motion, the acceleration a → at any point P R , θ on the…

Solution

For a particle in uniform circular motion, the acceleration a &#8594; at any point P R , &#952; on the…

Solution

For a particle in uniform circular motion, the acceleration a → at any point P R , θ on the…