For a 'p'-electron, the orbital angular momentum is

For a 'p'-electron, the orbital angular momentum is
  1. $\sqrt{6} \hbar$
  2. $\sqrt{2} \hbar$
  3. $\hbar$
  4. $2 \hbar$

Solution

Orbital angular momentum
$$
=\sqrt{l(l+1)} \hbar
$$
$=\sqrt{1(1+1)} \hbar=\sqrt{2} \hbar$ .

Asked in: JEE-TOPICTESTS-CHEMISTRY

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