For a $1^{\text {st }}$ order reaction if concentration is doubled then rate of reaction becomes
For a $1^{\text {st }}$ order reaction if concentration is doubled then rate of reaction becomes
- doubles
- half
- four times
- remains same.
Solution
For a first order reaction, rate $=k[A]$, when concentration of $A$ is doubled, the rate becomes double.
Asked in: MHT CET Full Test 12
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