For a light ray to undergo total internal reflection ( $\mathrm{i}=$ angle of incidence,…

For a light ray to undergo total internal reflection ( $\mathrm{i}=$ angle of incidence, $\mathrm{i}_{\mathrm{c}}=$ critical angle )
  1. light travels from denser to rarer medium and $\mathrm{i} \lt \mathrm{i}_{\mathrm{c}}$.
  2. light travels from rarer to denser medium and $\mathrm{i} \lt \mathrm{i}_{\mathrm{c}}$.
  3. light travels from denser to rarer medium and $\mathrm{i}\gt\mathrm{i}_{\mathrm{c}}$.
  4. light travels from rarer to denser medium and $\mathrm{i}\gt\mathrm{i}_{\mathrm{c}}$.

Solution

So in order for total internal reflection to take place; The rays of light must travel from a dense medium to a less dense medium. The angle of incidence must be greater than the critical angle.

Asked in: MHT CET 2024 (11 May Shift 1)

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