For a given reaction, Δ H = 35.5 k J m o l - 1 and Δ S = 83.6 J K - 1 m o l - 1 . The reaction is…

For a given reaction, ΔH=35.5 kJ mol-1 and ΔS=83.6 JK-1mol-1. The reaction is spontaneous at : (Assume that ΔH and ΔS do not vary with temperature)
  1. T < 425 K
  2. T > 425 K
  3. All temperatures
  4. T > 298 K

Solution

      ΔG=ΔH-TΔS
For a reaction to be spontaneous, ΔG= -ve
i.e., ΔH<TΔS
     T>ΔHΔS=35.5×103 J83.6 JK-1
i.e., T>425 K

Asked in: NEET 2017

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