For a given equilibrium reaction, addition of inert argon gas at constant volume can shift the equilibrium…

For a given equilibrium reaction, addition of inert argon gas at constant volume can shift the equilibrium in $\mathrm{N}_2(g)+3 \mathrm{H}_2(g) ightleftharpoons 2 \mathrm{NH}_3(g)$
  1. forward direction
  2. backward direction
  3. remain unaffected
  4. initially forward and then backward direction

Solution

The expression to $K_p$ of an equilibrium state at a given temperature for addition of inert gases is $K_p=K_n\left(\frac{p}{\Sigma n}ight)^{\Delta n_g} $where, volume is constant, $\left(\frac{p}{\Sigma n}ight)$ remains constant for any value of $\Delta n_g$. So, the given equilibrium reaction remains unaffected, if addition of inert Ar gas at constant volume. ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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