For a given combination of logic gates, the inputs $A, B$ and $C$ are as follows. $A=B=C=0$ and $A=B=1, C=0$…
For a given combination of logic gates, the inputs $A, B$ and $C$ are as follows. $A=B=C=0$ and $A=B=1, C=0$ then the logic states of output $D$ are respectively
0,0
0,1
1,0
1,1
Solution
The output $\mathrm{D}$ for the given combination:
$D=(A+\bar{B}) \cdot C=(A+\bar{B})+C$
If $A=B=C=0$ then $D=(0+\overline{0})+\overline{0}=\overline{0}+\overline{0}=1+1=1$
if $=B=1, C=0$ then $D=(1+\overline{1})+\overline{0}=\overline{1}+\overline{0}=0+1=1$
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