For a gas $\frac{R}{c_{v}}=0 \cdot 67$. This gas is made up of molecules which are
For a gas $\frac{R}{c_{v}}=0 \cdot 67$. This gas is made up of molecules which are
diatomic.
polyatomic.
monoatomic.
mixture of diatomic and polyatomic.
Solution
$\frac{R}{C_{v}}=0.67$
$\therefore \mathrm{R}=0.67 \mathrm{C}_{\mathrm{v}}$
$\therefore C_{p}-C_{v}=0.67 \mathrm{C}_{v}$
$\therefore C_{p}=1.67 \mathrm{C}_{v}$
$\therefore \gamma=\frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}}=1.67$
For a monoatomic gas $\gamma=\frac{5}{3}$ or $1.67$