For a gas having ' $\mathrm{X}$ ' degrees of freedom, ' $\gamma$ ' is $\left(\gamma=\right.$ ratio of…
For a gas having ' $\mathrm{X}$ ' degrees of freedom, ' $\gamma$ ' is $\left(\gamma=\right.$ ratio of specific heats $\left.=C_{\mathrm{P}} / \mathrm{C}_{\mathrm{V}}\right)$
$\frac{1+X}{2}$
$1+\frac{X}{2}$
$1+\frac{2}{X}$
$1+\frac{1}{X}$
Solution
$\gamma$ and degrees of freedom is related by
$\gamma=\frac{\mathrm{f}+2}{\mathrm{f}}$
Where $\mathrm{f}$ is the number of degrees of freedoms. Given $\mathrm{f}=\mathrm{X}$,
$\therefore \quad \gamma=\frac{X+2}{X}=1+\frac{2}{X}$