For a first order reaction, a plot of $\log (a-x)$ against time is a straight line with a negative slope…

For a first order reaction, a plot of $\log (a-x)$ against time is a straight line with a negative slope equal to
  1. $\frac{-k}{2.303}$
  2. $-2.303 k$
  3. $\frac{2.303}{k}$
  4. $-\frac{E_{a}}{2.303 R}$

Solution

$t=\frac{2.303}{k} \log \frac{a}{a-x}$
or $t=\frac{2.303}{k} \log a-\frac{2.303}{k} \log (a-x)$
$\log (a-x)=\frac{-k}{2.303} t+\log a$ .

Asked in: JEE-TOPICTESTS-CHEMISTRY

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