For a double strand DNA, one strand is given below: The amount of energy required to split the double strand…

For a double strand DNA, one strand is given below: The amount of energy required to split the double strand DNA into two single strands is _______ kcal $\mathrm{mol}^{-1}$. [Given: Average energy per $\mathrm{H}$-bond for A-T base pair $=1.0 \mathrm{kcal} \mathrm{mol}^{-1}, \mathrm{G}-\mathrm{C}$ base pair $=1.5 \mathrm{kcal}$ $\mathrm{mol}^{-1}$, and A-U base pair $=1.25 \mathrm{kcal} \mathrm{mol}^{-1}$. Ignore electrostatic repulsion between the phosphate groups.]

Solution

$\mathrm{A}=\mathrm{T} \quad 2 \mathrm{H}$-bond $\mathrm{G} \equiv \mathrm{C} \quad 3 \mathrm{H}$-bond Number of $\mathrm{A}=\mathrm{T}$ pair $=7$ Number of $\mathrm{G} \equiv \mathrm{C}$ pair $=6$ Number of H-bond involve in $\mathrm{A}=\mathrm{T}=7 \times 2=14$ Number of $\mathrm{H}$-bond involve in $\mathrm{G} \equiv \mathrm{C}=6 \times 3=18$ Energy required for $\mathrm{A}=\mathrm{T}=14 \times 1=14$ Energy required for $\mathrm{G} \equiv \mathrm{C}=18 \times 1.5=27$ Total energy required $14+27=41$

Asked in: JEE Advanced 2024 (Paper 2)

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