For a diatomic gas, if $\gamma_1=\left(\frac{C p}{C v}\right)$ for rigid molecules and…
- $\gamma_2=\gamma_1$
- $2 \gamma_2=\gamma_1$
- $\gamma_2 \lt \gamma_1$
- $\gamma_2 \gt \gamma_1$
Solution
$\begin{array}{ll}
& f=5 \\ \therefore & \gamma_1=\frac{7}{5}=1.4
\end{array}$
For non-rigid diatomic molecules
$\begin{array}{ll}
& f=5+2=7 \\ & \gamma_2=\frac{9}{7}=1.28 \\ \therefore & \gamma_1>\gamma_2
\end{array}$
Asked in: JEE Main 2025 (22 Jan Shift 2)